Potassium dichromate iron(II) sulfuric acid (K2Cr2O7 FeSO4 H2SO4) is accessible in nearly every chemical laboratory worldwide. In the H2SO4 medium, K2Cr2O7 and FeSO4 respond mainly. To balance the redox reaction we use the ion-electron technique.
Potassium dichromate reacts in sulfuric acid with iron(II) sulfate
The skeleton reaction of Potassium dichromate and iron(II) sulfate in sulfuric acid (K2Cr2O7 FeSO4 H2SO4) is–
K2Cr2O7 + FeSO4 + H2SO4 = Cr2(SO4)3 + Fe2(SO4)3 + K2SO4 + H2O
Or,
K2Cr2O7 + FeSO4 + H2SO4 = Cr2(SO4)3 + Fe2(SO4)3 + K2SO4 + H2O
Read more:
How to balance the redox reaction FeSO4 + KMnO4 + H2SO4 = Fe2(SO4)3 + MnSO4 + H2O + K2SO4
Here,
The Oxidizing agent: K2Cr2O7 or Cr2O72-
The Reducing agent: FeSO4 or, Fe2+
Oxidation Half Reaction:
⇒ Fe2+ – e– = Fe3+ … … … (1)
Reduction Half Reaction:
⇒ Cr2O72- + 6e– + 14H+ = 2Cr3+ + 7H2O … … … (2)
Now,
equation (1)x6 + (2),
6Fe2+ – 6e– = 6Fe3+
Cr2O72- + 14H+ + 6e– = 7H2O + 2Cr3+
14H+ + 6Fe2+ + Cr2O72- = 2Cr3+ + 7H2O + 6Fe3+
Now
adding necessary ions and radicals we get,
⇒ K2Cr2O7 + 6FeSO4 + 7H2SO4 = Cr2(SO4)3 + 3Fe2(SO4)3 + K2SO4 + 7H2O
“Answer”
K2Cr2O7 + 6FeSO4 + 7H2SO4 = Cr2(SO4)3 + 3Fe2(SO4)3 + K2SO4 + 7H2O
Follow us on Twitter, Facebook, Linkedin
Some really nice stuff on this web site, I like it
Thank you very much for your nice comment.
excellent post, very informative. I wonder why the other experts of this sector do not notice this. You must continue your writing. I’m sure, you have a huge readers’ base already!