Al H2SO4

Al + H2SO4 = Al2(SO4)3 +H2

When the Sulfuric acid is diluted, the Aluminium reacts with the diluted Sulfuric acid (Al H2SO4) to produce Aluminium sulfate as well as Hydrogen gas. The reaction is a Redox reaction. So The reaction is-

Al + H2SO4 (dil.) = Al2(SO4)3 +  H2

Click to know what happens when the Sulfuric acid is concentrated- Al + H2SO4 (conc) = ?

The above reaction is a Oxidation-Reduction reaction because-

  1. The Oxidation number of the Al in the reactants is zero and Al in the Aluminium sulfate at left side is +3.
  2. On the other hand the Oxidation number of the Hydrogen in the reactants is +1 but in the left side the Oxidation number is reduced to 0 . That means there is a change of electron between the reactants. That’s why  the reaction is a Redox reaction.

Aluminium Metal and Diluted Sulfuric acid (Al H2SO4 dil.)

Aluminium Metal is soft,  silvery-white as well as nonmagnetic. It is a very useful metal. It is a element of the periodic table having the atomic number 13.

On the other hand Diluted Sulfuric acid is a mineral acid. It is a colorless, odorless, and syrupy liquid that is soluble in water. In this reaction the Diluted Sulfuric acid acts as an acid only. Diluted Sulfuric acid does not have oxidizing power.

Like as other acids Diluted Sulfuric acid reacts with the aluminium and produce Hydrogen gas.

Balancing the equation of the reaction:

As the reaction is a redox reaction, the equation of the reaction can be balanced using the ion-electron method.

After balancing the equation of the reaction-

2Al + 3H2SO4 (dil.) = Al2(SO4)3 + 3H2

al h2so4

Prof (Using ion-Electron Method):

we can simple prof the above balance of the reaction equation using the Ion-Electron Method-

The skeleton reaction equation of the Aluminium with the diluted Sulfuric acid (Al H2SO4) is-

Al + H2SO4 (dil.) = Al2(SO4)3 + H2

Here,

The Oxidizing agent: H2SO4 or H+
The Reducing agent: Al

Oxidation Half Reaction:

Al – 3e = Al3+ … … … … (1)

Reduction Half Reaction:

2H++ 2e = H2 … … … … (2)

Now, equation (1)x2 + (2)x3,

2Al – 6e = 2Al3+

6H++ 6e = 3H2


2Al + 6H+ = 2Al3+ + 3H2

Or, adding necessary ions and radicals we get,

2Al + 3H2SO4 = Al2(SO4)3 + 3H2

Click on the reaction to learn balancing redox reaction easily by ion electron method

Man needs his difficulties because they are necessary to enjoy success.

-A. P. J. Abdul Kalam

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