kmno4 h2o2 h2so4

KMnO4 + H2O2 + H2SO4 = O2 + MnSO4 + K2SO4 + H2O

Hydrogen peroxide potassium permanganate and  sulfuric acid (kmno4 h2o2 h2so4) are available in almost all chemical lab across the World. Mainly KMnO4 and H2O2 react in the H2SO4 medium. We use the ion-electron method to balance the redox reaction.

Hydrogen peroxide react with potassium permanganate and sulfuric acid

H2O2 + KMnO4 + H2SO4 = O2 + MnSO4 + K2SO4 + H2O

or, After balancing the Redox reaction

5H2O2 + 2KMnO4 + 3H2SO4 = 5O2 + 2MnSO4 + K2SO4 + 8H2O

Now by using the ino-electron method we can balance the Oxidation-Reduction reaction.

kmno4 h2o2 h2so4

The skeleton reaction for the redox reaction of Hydrogen peroxide potassium permanganate and  sulfuric acid (kmno4 h2o2 h2so4) is-

H2O2 + KMnO4 + H2SO4 = O2 + MnSO4 + K2SO4 + H2O

Here,

The Oxidizing agent: KMnO4 or MnO4-1

The Reducing agent: H2O2 or, O-1

Reduction Half Reaction:

MnO-1 +5e + 8H = Mn2- + 4H2O … …. …. …. (1)

Oxidation Half Reaction:

2O-1– 2e = O2 … … … … (2)

Now,

equation (1)x2 + (2)x5,

2MnO-1 +10e + 16H = 2Mn2- + 8H2O

10 O-1– 10e = 5O2


2MnO-1 + 10 O-1 + 16H+= 2Mn2- + 8H2O +5O2

or, adding necessary ions and radicals we get,

5H2O2 + 2KMnO4 + 3H2SO4 = 5O2 + 2MnSO4 + K2SO4 + 8H2O

“Answer”

5H2O2 + 2KMnO4 + 3H2SO4 = 5O2 + 2MnSO4 + K2SO4 + 8H2O

Click on the reaction to learn balancing redox reaction easily by ion electron method

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