KMnO4 + H2O2 + H2SO4 = O2 + MnSO4 + K2SO4 + H2O

Hydrogen peroxide potassium permanganate and  sulfuric acid (kmno4 h2o2 h2so4) are available in almost all chemical lab across the World. Mainly KMnO4 and H2O2 react in the H2SO4 medium. We use the ion-electron method to balance the redox reaction.

Hydrogen peroxide react with potassium permanganate and sulfuric acid

H2O2 + KMnO4 + H2SO4 = O2 + MnSO4 + K2SO4 + H2O

or, After balancing the Redox reaction

5H₂O₂ + 2KMnO₄ + 3H₂SO₄ = 5O₂ + 2MnSO₄ + K₂SO₄ + 8H₂O

Now by using the ino-electron method we can balance the Oxidation-Reduction reaction.

The skeleton reaction for the redox reaction of Hydrogen peroxide potassium permanganate and  sulfuric acid (kmno4 h2o2 h2so4) is-

H2O2 + KMnO4 + H2SO4 = O2 + MnSO4 + K2SO4 + H2O

Here,

The Oxidizing agent: KMnO₄ or MnO₄^-1

The Reducing agent: H₂O₂ or, O^-1

Reduction Half Reaction:

MnO₄ ^-1 +5e + 8H⁺  = Mn^2- + 4H₂O … …. …. …. (1)

Oxidation Half Reaction:

2O^-1– 2e = O₂ … … … … (2)

Now,

equation (1)x2 + (2)x5,

2MnO₄ ^-1 +10e + 16H⁺  = 2Mn^2- + 8H₂O

10 O^-1– 10e = 5O₂

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2MnO₄ ^-1 + 10 O^-1 + 16H⁺= 2Mn^2- + 8H₂O +5O₂

or, adding necessary ions and radicals we get,

5H₂O₂ + 2KMnO₄ + 3H₂SO₄ = 5O₂ + 2MnSO₄ + K₂SO₄ + 8H₂O

“Answer”

5H₂O₂ + 2KMnO₄ + 3H₂SO₄ = 5O₂ + 2MnSO₄ + K₂SO₄ + 8H₂O

Click on the reaction to learn balancing redox reaction easily by ion electron method

• K₂Cr₂O₇ + FeSO₄ + H₂SO₄ = Cr₂(SO₄)₃ + Fe₂(SO₄)₃ + K₂SO₄ + H₂O (click here)
• FeSO₄ + KMnO₄ + H₂SO₄ = Fe₂(SO₄)₃ + MnSO₄ + K₂SO₄ + H₂O (click here)
• NaCl + KMnO₄ + H₂SO₄  = Cl₂ + MnSO₄+ Na₂SO₄ + K₂SO₄+ H₂O (click here)

Imagination is more important than knowledge.

-Albert Einstein