NaCl + KMnO4 + H2SO4 = Cl2 + MnSO4 + Na2SO4 + K2SO4 + H2O

NaCl + KMnO4 + H2SO4 react with each other to produce the free chlorin ions. This is a Redox reaction.

Sodium chloride react with potassium permanganate and sulfuric acid

The skeleton formula of the reaction is-

NaCl + KMnO4 + H2SO4 = Cl2 + MnSO4+ Na2SO4 + K2SO4+ H2O

This is an oxidation-reduction (redox) reaction.

The KMnO4 acts as the agent of oxidation as well as NaCl acts as the agent of reduction. Oxidizing agent: KMnOor MnO-1

Reducing agent: NaCl or Cl-1

Oxidation Half Reaction:

⇒ MnO-1 +5e + 8H = 4H2O + Mn2- … …. …. …. (1)

Reduction Half Reaction

Cl-1 – e = Cl… … … … … (2)

Now equation (1) + (2)x5,

MnO-1 +5e + 8H = 4H2O + Mn2-

5Cl-1 – 5e = 5Cl0

⇒ MnO-1 + 5Cl-1+ 8H = 5Cl0 + Mn2- + 4H2O

or, MnO-1 + 5Cl-1+ 8H = 5/2 Cl2 + Mn2- + 4H2O

or, 2MnO-1 + 10Cl-1+ 16H = 5Cl2 + 2Mn2- + 8H2O

Now adding necessary ions and radicals we get,

⇒ 2KMnO4 + 10NaCl+ 8H2SO4  = 5Cl2 + 2MnSO4 + 8H2O + 5Na2SO4 +K2SO4

⇒ 2KMnO4 + 10NaCl+ 8H2SO4 = 5Cl2 + 2MnSO4+ 5Na2SO4 + 8H2O + K2SO4

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