h2s kmno4 h2so4

H2S + KMnO4 + H2SO4 = S + MnSO4 + K2SO4 + H2O

Hydrogen sulphied potassium permanganate and sulfuric acid (H2S KMnO4 H2SO4) are available in almost all chemical lab across the World. Mainly KMnO4 and H2S react in the H2SO4 medium. The reaction is a Redox reaction.

H2S KMnO4 H2SO4

Hydrogen sulfide is the chemical compound with the chemical formula H2S. It is a colorless gas with the characteristic foul odor of rotten eggs. Besides it is very poisonous as well as corrosive and flammable also.

Potassium permanganate is an inorganic chemical compound and medication. It is a strong oxidizing agent. KMnOis a salt consisting of K+ and MnO4 -1  ions and has the chemical formula KMnO. It dissolves in water to give intensely pink or purple solutions. In Solid state it forms  prismatic purplish-black glistening crystals.

Sulfuric acid is a mineral acid with molecular formula H₂SO₄. It is a colorless, odorless, and syrupy liquid that is soluble in water. In this reaction it acts as an acidic medium only.

Hydrogen sulphide reacts with potassium permanganate and sulfuric acid

Hydrogen sulphide reacts with potassium permanganate and sulfuric acid to produce Sulfer, Manganese Sulfate, potassium sulfate as well as water.

H2S + KMnO4 + H2SO4 = S + MnSO4 + K2SO4 + H2O

Now by using the ion-electron method we can balance the Oxidation-Reduction reaction.

h2s kmno4 h2so4

Ion-Electron method

Ion-electron method is a very effective method to balance equations of the Redox reactions. As the above reaction is a redox reaction, we can use the ion-electron method to balance the reaction equation. Let’s try-

The skeleton reaction for the redox reaction is-

H2S + KMnO4 + H2SO4 = S + MnSO4 + K2SO4 + H2O

Here,
The Oxidizing agent: KMnO4 or MnO4-1
The Reducing agent: H2S or, S-2

Reduction Half Reaction:

MnO-1 +5e + 8H = Mn2- + 4H2O … …. …. …. (1)

Oxidation Half Reaction:

S-2 – 2e = S … … … … (2)

Now,

equation (1)x2 + (2)x5,

2MnO-1 +10e + 16H = 2Mn2- + 8H2O

5S-2 – 10e = 5S


2MnO4 -1 + 5 S-2 + 16H+ = 2Mn2- + 8H2O +5S

⇒ adding necessary ions and radicals we get,

5H2S + 2KMnO4 + 3H2SO4 = 5S + 2MnSO4 + K2SO4 + 8H2O

“Answer”

5H2S + 2KMnO4 + 3H2SO4 = 5S + 2MnSO4 + K2SO4 + 8H2O

Click on the reaction to learn balancing redox reaction easily by ion electron method

Try not to become a man of success, but rather try to become a man of value.

-Albert Einstein

Leave a Reply

Your email address will not be published.


*